Unlocking Quadratic Equations: A Friendly Guide to Solving 3x² = 6x + 45

You know, sometimes math problems can feel like a locked door, and you're just searching for the right key. Take an equation like 3x² = 6x + 45. At first glance, it might seem a bit daunting, especially if you're not a seasoned mathematician. But honestly, it's more about understanding the process than having some innate genius.

This particular equation is a classic example of a quadratic equation, and the reference material points us towards a specific method for solving it: completing the square. It sounds a bit technical, doesn't it? But let's break it down, like we're just chatting over coffee.

First things first, we want to get the equation into a more manageable form. The standard form for a quadratic equation is ax² + bx + c = 0. Our equation, 3x² = 6x + 45, needs a little rearranging. If we move everything to one side, we get 3x² - 6x - 45 = 0.

Now, the 'completing the square' method works best when the coefficient of x² (that's the 'a' term) is 1. So, we'll divide the entire equation by 3. This gives us x² - 2x - 15 = 0.

Here's where the 'completing the square' magic happens. We want to isolate the x² and x terms on one side and the constant on the other. So, let's move that -15 over: x² - 2x = 15.

Now, think about what we need to add to x² - 2x to make it a perfect square trinomial. Remember, a perfect square trinomial looks like (x + k)² or (x - k)². If we expand (x - k)², we get x² - 2kx + k². Comparing this to our x² - 2x, we can see that -2k must equal -2. That means k is 1.

So, we need to add k², which is 1², or just 1, to both sides of our equation. This keeps things balanced. So, x² - 2x + 1 = 15 + 1.

On the left side, we now have a perfect square: (x - 1)². And on the right side, we have 16. So, our equation is now (x - 1)² = 16.

This is much simpler! We can now use the 'square root property'. If something squared equals 16, then that something must be either the positive or negative square root of 16. So, x - 1 = ±√16.

This means x - 1 = 4 or x - 1 = -4.

Solving for x in each case:

If x - 1 = 4, then x = 4 + 1, which gives us x = 5.

If x - 1 = -4, then x = -4 + 1, which gives us x = -3.

And there you have it! The solutions to 3x² = 6x + 45 are x = 5 and x = -3. See? Not so scary after all. It's just a series of logical steps, and with a little practice, these kinds of problems become quite familiar. It’s like learning a new dance – a few awkward steps at first, but soon you’re moving with confidence.

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