When you think about setting up a pool, one of the first questions that might pop into your mind is: how much water will it hold? For an 18-foot by 48-inch above-ground pool, this calculation can be surprisingly straightforward. The volume of water in a cylindrical pool can be determined using the formula:
Volume = π × r² × h
Here, 'r' represents the radius and 'h' stands for height. In our case:
- The diameter of the pool is 18 feet, so the radius (r) would be half of that—9 feet.
- The height (h) is given as 48 inches; to keep things consistent with our units, we convert this to feet. Since there are 12 inches in a foot, we divide by 12: 48 ÷ 12 = 4 feet.
Now plugging these values into our formula gives us:
Volume = π × (9 ft)² × (4 ft) = π × 81 ft² × 4 ft ≈ 1,013.76 cubic feet.
To convert cubic feet to gallons—a crucial step since most people measure their pools in gallons—we use another conversion factor: 1 cubic foot equals approximately 7.48 gallons. So, you multiply: 1,013.76 cu ft × 7.48 gal/cu ft ≈ 7,578 gallons.
That’s quite a bit of water! Knowing this number not only helps you prepare for filling your new oasis but also aids in understanding maintenance needs like chemical balancing and heating costs throughout those hot summer days when everyone wants to take a dip.